JavaScript Array sort() Method

2024-06-18 13:28| 来源: 网络整理| 查看: 265

JavaScript Array sort() ❮ Previous JavaScript Array Reference Next ❯ Examples // Create an Array const fruits = ["Banana", "Orange", "Apple", "Mango"];

// Sort the Array fruits.sort();

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Description

The sort() method sorts the elements of an array.

The sort() method sorts the elements as strings in alphabetical and ascending order.

The sort() method overwrites the original array.

See Also:

The Array reverse() Method

Sort Compare Function

Sorting alphabetically works well for strings ("Apple" comes before "Banana").

But, sorting numbers can produce incorrect results.

"25" is bigger than "100", because "2" is bigger than "1".

You can fix this by providing a "compare function" (See examples below).

Syntax array.sort(compareFunction) Parameters Parameter Description compareFunction Optional.A function that defines a sort order. The function should return a negative, zero, or positive value, depending on the arguments: function(a, b){return a-b}

When sort() compares two values, it sends the values to the compare function, and sorts the values according to the returned (negative, zero, positive) value.

Example:

The sort function will sort 40 as a value lower than 100.

When comparing 40 and 100, sort() calls the function(40,100).

The function calculates 40-100, and returns -60 (a negative value).

Return Value TypeDescription ArrayThe array with the items sorted. More Examples Sort Decending

Sort and then reverse the order:

// Create an Array const fruits = ["Banana", "Orange", "Apple", "Mango"];

// Sort the Array fruits.sort();

// Reverse the array fruits.reverse();

Try it Yourself » Numeric Sorts Using a Sort Function

Sort numbers in ascending order: